Counterexample of the Riemann Hypothesis

27 June 2022, Version 9
This content is an early or alternative research output and has not been peer-reviewed by Cambridge University Press at the time of posting.

Abstract

Under the assumption that the Riemann hypothesis is true, von Koch deduced the asymptotic formula $\theta(x) = x + O(\sqrt{x} \times \log^{2} x)$. A precise version of this was given by Schoenfeld. He found under the assumption that the Riemann hypothesis is true that $\left| \theta(x) - x \right| < \frac{1}{8 \times \pi} \times \sqrt{x} \times \log^{2} x$ for every $x \geq 599$. Using this result, we prove that if the Riemann hypothesis is true, then $\prod_{q \leq x} \frac{q}{q-1} < \left(e^{\gamma} \times \log x\right) \times \left(1 - \frac{\log x}{8 \times \pi \times \sqrt{x}}\right)$ for every $x \geq 599$. Hence, we obtain that if the Riemann hypothesis is true, then $x^{\left(1 - \frac{\log x}{8 \times \pi \times \sqrt{x}}\right)} > \theta(x)$ for every $x \geq 599$. However, this is false since $(\theta(x) - x)$ changes sign infinitely often. By contraposition, the Riemann hypothesis is false.

Keywords

Riemann hypothesis
Nicolas inequality
Chebyshev function
Prime numbers

Supplementary weblinks

Comments

Comments are not moderated before they are posted, but they can be removed by the site moderators if they are found to be in contravention of our Commenting and Discussion Policy [opens in a new tab] - please read this policy before you post. Comments should be used for scholarly discussion of the content in question. You can find more information about how to use the commenting feature here [opens in a new tab] .
This site is protected by reCAPTCHA and the Google Privacy Policy [opens in a new tab] and Terms of Service [opens in a new tab] apply.