There exists a subset of N which is not listable and has a short description in terms of arithmetic

26 February 2026, Version 3
This content is an early or alternative research output and has not been peer-reviewed by Cambridge University Press at the time of posting.

Abstract

We prove that the set {n∈N: ∃p,q∈N ((n=2^p \cdot 3^q) ∧ ∀(x_0,...,x_p)∈N^{p+1} ∃(y_0,...,y_p)∈{0,...,q}^{p+1} ((∀k∈{0,...,p} (1=x_k ⇒ 1=y_k)) ∧ (∀i,j,k∈{0,...,p} (x_i+x_j=x_k ⇒ y_i+y_j=y_k)) ∧ (∀i,j,k∈{0,...,p} (x_i \cdot x_j=x_k ⇒ y_i \cdot y_j=y_k))))} is not listable.

Keywords

arithmetic of N
computable function
eventual domination
Hilbert’s 10th problem
limit-computable function
listable subset of N
undecidable decision problem

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Comment number 1, Eldar Garaev: Feb 26, 2026, 19:18

useful sources of literature are indicated