Abstract
Abstract
This paper presents an elementary algebraic approach attempting to prove Fermat's Last Theorem, which states that no three positive integers \(a\), \(b\), and \(c\) satisfy the equation \(a^n + b^n = c^n\) for any integer value of \(n > 2\). By segmenting the relationship between the bases into three distinct trichotomy cases—\(a+b=c\), \(a+bc\)—the author utilizes binomial expansions to isolate cross-terms and establish inequalities. While the first two cases successfully demonstrate that no solutions exist, the third case introduces strict inequality bounds (\(k > h\)) on the expansion remainders to force a contradiction. Analysis reveals that this boundary condition implicitly assumes the non-existence of a solution, resulting in circular logic that invalidates the final contradiction.



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