Fermat's Last Theorem (3 Lines Way)
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Taha, I watched your YouTube video. I'm afraid that you are completely wrong about nearly everything you say. I'll bring up the following points.*** 1. You have NOT solved any of these open problems. You only think you solved them, but anyone who is trained in mathematics can easily pinpoint basic errors in your proofs that completely invalidate them. You have only deluded yourself into thinking you solved them. You need to stop saying that you solved them. 2. The reason why gatekeeping exists is NOT to prevent independent researchers from publishing (Yitang Zhang's breakthrough paper on prime gaps, while he was only a lecturer, is a good example of this). It is to prevent low-quality work and junk papers (such as yours) from wasting the reviewers' time. If you were to submit any of your papers to a top journal, it will be rejected almost instantly. 3. The reason it'll be rejected without review is, again, NOT because you call yourself an independent researcher. It is because your papers fall way below the standard expected in publishing. You have no literature review, badly typeset equations, nothing that remotely convinces anyone that you're an expert on the subject. That's on top of the basic mistakes within your proofs. 4. Nobody in academia cares about view count. Having lots of views does not make you right. You are behaving like a "mathematical crank" - look up that phrase on Google. You possess all of the traits of a crank. I encourage you to stop pursuing this path, for your own good.
https://docs.google.com/document/d/1srI9pXGqI2GIlaFI8pv0Dcujbs1SwXVW1t28YgF1imo/edit?usp=sharing Google Doc. Fermat & Taha's Binomial Fact
https://youtu.be/XM8zXXG2z-s
The binomial expansion of ((a-u) + (b-v))^n will contain powers of a-u and b-v, where each of them has their own binomial expansion containing positive and negative terms. You cannot simply claim that the sum of all the additional terms beyond a^n and b^n is nonzero. Moreover, this "proof" does not invoke the condition n>2 anywhere, so you could technically "prove" that a^2 + b^2 = c^2 has no positive integer solutions, which is false. Yet again, another failed attempt at proof.



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